# How To Solve Parallel Circuit Problems

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For Figure, the sum of the potential drop of each resistor and the voltage supplied by the voltage source should equal zero:$V - V_1 - V_2 - V_3 = 0,$$V = V_1 V_2 V_3,$$= IR_1 IR_2 IR_3,$$I = \frac = \frac.$Since the current through each component is the same, the equality can be simplified to an equivalent resistance, which is just the sum of the resistances of the individual resistors.

Any number of resistors can be connected in series.

The equivalent resistance of a set of resistors in a series connection is equal to the algebraic sum of the individual resistances.

In Figure, the current coming from the voltage source flows through each resistor, so the current through each resistor is the same.

The sum of the individual currents equals the current that flows into the parallel connections.

Resistors are said to be in series whenever the current flows through the resistors sequentially.The current through the circuit depends on the voltage supplied by the voltage source and the resistance of the resistors.For each resistor, a potential drop occurs that is equal to the loss of electric potential energy as a current travels through each resistor.According to Ohm’s law, the potential drop is the resistance in ohms $$(\Omega)$$.Since energy is conserved, and the voltage is equal to the potential energy per charge, the sum of the voltage applied to the circuit by the source and the potential drops across the individual resistors around a loop should be equal to zero:$\sum_^N V_i = 0.$This equation is often referred to as Kirchhoff’s loop law, which we will look at in more detail later in this chapter.They solve for total resistance and current, the current through each resistor, the voltage across each resistor, and the power dissipated.Z_T =((70 60j)(40-25j))/(110 35j) =((92.20/_40.60^text(o))(47.17/_-32.01^text(o)))/(115.4/_17.65^text(o)) (We do the product on the top first.) =((92.20xx47.17)/_(40.60^text(o)-32.01^text(o)))/(115.4/_17.65^text(o)) =(4349.074/_8.59^text(o))/(115.4/_17.65^text(o)) (Now we do the division.) =(4349.074)/115.4/_(8.59^text(o)-17.65^text(o)) =37.69/_-9.06^text(o) (We convert back to rectangular form.) =37.22-5.93j A 100\ Ω resistor, a 0.0200\ "H" inductor and a 1.20\ mu"F" capacitor are connected in parallel with a circuit made up of a 110\ Ω resistor in series with a 2.40\ mu"F" capacitor.The equivalent resistance of a combination of resistors depends on both their individual values and how they are connected.The simplest combinations of resistors are series and parallel connections (Figure).In a series circuit, the equivalent resistance is the algebraic sum of the resistances.The current through the circuit can be found from Ohm’s law and is equal to the voltage divided by the equivalent resistance.

## Comments How To Solve Parallel Circuit Problems

• ###### Resistors in Series and Parallel Resistor Combinations
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Electronics Tutorial about Resistors in Series and Parallel Circuits, Connecting Resistors in. using the formula for two parallel connected resistors as follows.…

• ###### Physics for Kids Resistors in Series and Parallel - Ducksters
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Sample problem Using the circuit diagram below, solve for the value of the missing resistance R. Answer First we'll figure out the. What do you do when you have a circuit with both parallel and series resistors? The idea for solving these.…

• ###### How to Solve a Basic Parallel or Series Circuit 5 Steps with Pictures
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How to Solve a Basic Parallel or Series Circuit When it comes to electrical engineering, solving circuits is a fundamental skill. Before beginning this instructable.…

• ###### Parallel Resistor Calculator R1 + R2 = equivalent resistor R resistance.
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Parallel Resistor Calculator R1 + R2 = R equivalent resistance circuit equivalent total resistor. Notice This calculator can also solve other math problems.…

• ###### Series Parallel Circuits
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Label all nodes. Solve the problem Reduce and Return Approach. 6. Reduce and Return Approach. Series and parallel elements from a must be combined.…

• ###### Combined Series-Parallel Circuits Read Physics CK-12 Foundation
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Jun 26, 2013. Demonstrates the problem solving techniques for electrical circuits that include both series and parallel component circuits.…

• ###### Series-Parallel Combinations - Fundamentals of Electricity
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When a simple series or parallel circuit is obtained, this circuit is solved. Results can then. original circuit. For the example problem this will require two steps.…

• ###### Ninja Circuit Analysis Tricks + bonus resistor tricks! CircuitCrush.
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Last time I promised to reveal a few tricks that work on certain parallel circuits. Recall from the first post in this series that parallel resistors add up with the formula below. The problem is that doing calculations like this is tedious and boring.…