*, using values from previous calculations: Given: Solution: Now that you have solved for the unknown quantities in this circuit, you can apply what you have learned to any series, parallel, or combination circuit.*It is important to remember to first look at the circuit and from observation make your determination of the type of circuit, what is known, and what you are looking for.

So we're given that I is 2.35 amps and I two, the current through the R two resistor is 1.61 amps.

To demonstrate the method used to solve combination circuit problems, the network shown in figure 3-54(A) will be used to calculate various circuit quantities, such as resistance, current, voltage, and power. The equivalent resistance of this circuit (total resistance) can now be calculated.

Given: Solution: The original circuit can be redrawn with a single resistor that represents the equivalent resistance of the entire circuit as shown in figure 3-54(C).

Then we solve this for I three and we move this to the right hand side making it positive and then divide both sides by R three and we solve for I three.

So I three is V t minus I times R one over R three.

## Comments Solving Series Parallel Circuits Problems

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